Yig'indini ko'paytmaga almashtirib hisoblang: $17-6+17-6+\ldots+17-6$ (48 ta son)
- A. 132
- B. 261
- C. 264
- D. 262
Natural sonlar va ular ustida amallar bo‘yicha savol
Javob va yechimni ko‘rish
Javob: 264
Har bir qavs ichidagi $17-6$ ifodasi $11$ ga teng, shuning uchun ifodani $48$ marta takrorlanayotgan $11$ sonining yig'indisi sifatida yozishimiz mumkin:
\[
\underbrace{(17-6)+(17-6)+\dots+(17-6)}_{48\ \text{marta}}=48\cdot 11.
\]
$48\cdot 11$ ni hisoblasak, $48\cdot 10=480$, $48\cdot 1=48$, ularning yig'indisi $480+48=528$.
Bu sonni $2$ ga bo‘linadigan ko‘paytma sifatida ifodalash uchun $528=2\cdot 264$, ya’ni kerakli natija $264$ ga teng.
Javob: **C) 264**.
Mavzuni mustahkamlang
Bu savol Natural sonlar va ular ustida amallar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganish