MathTest.uz
Algebra · orta

Natural sonlar va ular ustida amallar bo‘yicha savol

Qulay usulda hisoblang: $12+24+36+64+76+88$
  1. A. 297
  2. B. 600
  3. C. 300
  4. D. 299
Javob va yechimni ko‘rish

Javob: 300

Berilgan sonlarni juft‑juft yig‘indiga ajrating: $12+24+36$ va $64+76+88$. Birinchi uchta son $12,24,36$ hammasi $12$ ga bo‘linadi, shuning uchun $12(1+2+3)=12\cdot6=72$. Ikkinchi uchta son $64,76,88$ ham $4$ ga bo‘linadi, $4(16+19+22)=4\cdot57=228$. Endi ikki qismni qo‘shamiz: $72+228=300$. Demak, to‘g‘ri javob **C) 300**.

Mavzuni mustahkamlang

Bu savol Natural sonlar va ular ustida amallar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

Mavzuni o‘rganish

Shu mavzudagi boshqa savollar