Ifodani soddalashtiring: $\frac{x^2 - 9}{x^2 + 6x + 9} \cdot \frac{x + 3}{x - 3}$
- A. $1$
- B. $\frac{x-3}{x+3}$
- C. $\frac{x+3}{x-3}$
- D. $x+3$
Algebraik kasrlar bo‘yicha savol
Javob va yechimni ko‘rish
Javob: $1$
Mavzuni mustahkamlang
Bu savol Algebraik kasrlar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganishShu mavzudagi boshqa savollar
Kasrlarni ayiring: $\frac{2a}{a^2 - b^2} - \frac{1}{a - b}$Tenglamani yeching: $\frac{x}{x-2} - \frac{2}{x-2} = 1$Ifodani soddalashtiring: $\left(\frac{1}{x} + \frac{1}{y}\right) : \frac{x^2 - y^2}{xy}$Agar $x + \frac{1}{x} = 5$ bo'lsa, $x^2 + \frac{1}{x^2}$ ning qiymatini toping.Kasrni qisqartiring: $\frac{2a^2 - 8}{a^2 - 4a + 4}$