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Algebra · oson

Natural sonlar va ular ustida amallar bo‘yicha savol

Ko'p xonali sonni xona birliklari yig'indisi ko'rinishida yozing: 129807
  1. A. $1\cdot 100000+2\cdot 10000+9\cdot 1000+7\cdot 100+7$
  2. B. $1\cdot 100000+2\cdot 10000+8\cdot 1000+8\cdot 100+7$
  3. C. $2\cdot 100000+2\cdot 10000+9\cdot 1000+8\cdot 100+7$
  4. D. $1\cdot 100000+2\cdot 10000+9\cdot 1000+8\cdot 100+7$
Javob va yechimni ko‘rish

Javob: $1\cdot 100000+2\cdot 10000+9\cdot 1000+8\cdot 100+7$

Ko'p xonali sonni har bir uning raqamiga mos keluvchi birlik, o'nlik, yuzlik, minglik, ... koeffitsientlari bilan yozamiz. 129807 sonida $1$ minglik $10^{5}$, $2$ minglik $10^{4}$, $9$ minglik $10^{3}$, $8$ yuzlik $10^{2}$ va $7$ birlik $10^{0}$ mavjud. Shuning uchun sonni $1\cdot 100000+2\cdot 10000+9\cdot 1000+8\cdot 100+7$ shaklida ifodalash to‘g‘ri. Bu ifoda variant D ga mos keladi.

Mavzuni mustahkamlang

Bu savol Natural sonlar va ular ustida amallar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

Mavzuni o‘rganish

Shu mavzudagi boshqa savollar

Hisoblang: $354 + 246$$7+5$ ning natijasi nechiga teng?$1+2+3+4+5$ yig'indisi nechiga teng?$3\cdot 2+7\cdot 13$$8\cdot 3+7\cdot 6-5\cdot 9$