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Algebra · qiyin

Ildizli ifodalar bo‘yicha savol

Hisoblang: $\sqrt{\sqrt{17 - 12\sqrt{2}} \cdot \sqrt{3 + 2\sqrt{2}}} : \frac{\sqrt{3}}{\sqrt{12}}$
  1. A. $1$
  2. B. $2\sqrt{\sqrt{2}-1}$
  3. C. $3$
  4. D. $4$
Javob va yechimni ko‘rish

Javob: $2\sqrt{\sqrt{2}-1}$

Ichki ildizlar: √(17−12√2)=3−2√2 va √(3+2√2)=1+√2. Ularning ko‘paytmasi √2−1. Tashqi ildiz √(√2−1), bo‘luvchi √3/√12=1/2. Natija 2√(√2−1). To‘g‘ri javob: B.

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