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Geometriya · orta

Uchburchaklar o'xshashligi bo‘yicha savol

BC \parallel DE; EG \parallel AF; AD = 3; BD = 12; EG = 6; AF = x; ?
Uchburchaklar o'xshashligi savolining chizmasi
  1. A. $7,5$
  2. B. $8$
  3. C. $6$
  4. D. $9$
Javob va yechimni ko‘rish

Javob: $7,5$

AB=AD+DB=3+12=15. DE parallel BC bo‘lgani uchun ADE va ABC uchburchaklar o‘xshash: AE/AC=AD/AB=1/5. Demak, CE/CA=4/5. EG parallel AF bo‘lgani uchun CEG va CAF uchburchaklar ham o‘xshash; EG/AF=CE/CA=4/5. Shunday qilib, AF=6·5/4=7,5. To‘g‘ri javob: A.

Mavzuni mustahkamlang

Bu savol Uchburchaklar o'xshashligi mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

Mavzuni o‘rganish

Shu mavzudagi boshqa savollar

Uchburchaklar o'xshashligi: $\angle BAC = 72^\circ$; $\angle ABC = 64^\circ$; $\angle MKN = \gamma = ?$Uchburchaklar o'xshashligi: $\angle NMK = 84^\circ$; $\angle NKM = 48^\circ$; $\angle ABC = \beta = ?$Uchburchaklar o'xshashligi: $AB = 10$; $BC = 15$; $AC = 20$; $MN = 4$; $NK = y$; $MK = x$; $x + y = ?$Uchburchaklar o'xshashligi: $AB = 15$; $BC = 20$; $AC = 30$; $MN = 9$; $NK = y$; $MK = x$; $x - y = ?$Uchburchaklar o'xshashligi: $AB = 12$; $BC = y$; $AC = 18$; $MN = 4$; $NK = 5$; $MK = x$; $y + 2x = ?$