$ABCD$ - parallelogramm; $\angle BAD = x$; $\angle ABC = 2x$; $x = ?$
- A. $60^{\circ}$
- B. $45^{\circ}$
- C. $30^{\circ}$
- D. $90^{\circ}$
Parallelogramm va uning xossalari bo‘yicha savol
Javob va yechimni ko‘rish
Javob: $60^{\circ}$
Mavzuni mustahkamlang
Bu savol Parallelogramm va uning xossalari mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganishShu mavzudagi boshqa savollar
$ABCD$ - parallelogramm; $\angle BAD = x$; $\angle ABC = 3x$; $x = ?$$ABCD$ - parallelogramm; $\angle BAD = x$; $\angle ABC = \beta$; $\angle BCD = 80^\circ - x$; $\beta = ?$$ABCD$ - parallelogramm; $\angle BAD = 2x$; $\angle ABC = \beta$; $\angle BCD = 96^\circ - x$; $\beta = ?$$ABCD$ - parallelogramm; $BE \perp AD$; $\angle ABE = 42^\circ$; $\angle BCD = x = ?$$ABCD$ - parallelogramm; $BE \perp DC$; $\angle CBE = 36^\circ$; $\angle BAD = x = ?$