Perimetri 22 m ga teng bo'lgan to'g'ri to'rtburchakning bo'yi 7 m ga teng bo'lsa, uning yuzini toping.
- A. 28 m2
- B. 30 m2
- C. 33 m2
- D. 26 m2
Geometrik shakllar bo‘yicha savol
Javob va yechimni ko‘rish
Javob: 28 m2
To‘g‘ri to‘rtburchakning perimetri formulasi $P=2(l+w)$, bu yerda $l$ – uzunlik, $w$ – bo‘yi. Perimetri $22$ m va $w=7$ m berilgan, shuning uchun
$$2(l+7)=22 \;\Longrightarrow\; l+7=11 \;\Longrightarrow\; l=4\text{ m}.$$
Yuzini topish uchun $S=l\cdot w$ formulasidan foydalanamiz:
$$S=4\cdot 7=28\ \text{m}^2.$$
Demak, to‘g‘ri to‘rtburchakning yuzi $28\ \text{m}^2$ ga teng, ya'ni variant **A**.
Mavzuni mustahkamlang
Bu savol Geometrik shakllar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganish