$x\notin\{-1,0,1\}$ uchun kasrlarni qo‘shing: $\frac{x-1}{x^2-x}+\frac{1}{x+1}$.
- A. $\frac{2}{x+1}$
- B. $\frac{2x+1}{x(x+1)}$
- C. $\frac{2}{x(x+1)}$
- D. $\frac{x+2}{x+1}$
Algebraik kasrlar bo‘yicha savol
Javob va yechimni ko‘rish
Javob: $\frac{2x+1}{x(x+1)}$
Birinchi kasr $1/x$ ga teng. Umumiy maxrajga keltirsak, surat $(x+1)+x=2x+1$ bo‘ladi.
Mavzuni mustahkamlang
Bu savol Algebraik kasrlar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganishShu mavzudagi boshqa savollar
Ifodani soddalashtiring: $\frac{x^2 - 9}{x^2 + 6x + 9} \cdot \frac{x + 3}{x - 3}$Kasrlarni ayiring: $\frac{2a}{a^2 - b^2} - \frac{1}{a - b}$Tenglamani yeching: $\frac{x}{x-2} - \frac{2}{x-2} = 1$Ifodani soddalashtiring: $\left(\frac{1}{x} + \frac{1}{y}\right) : \frac{x^2 - y^2}{xy}$Agar $x + \frac{1}{x} = 5$ bo'lsa, $x^2 + \frac{1}{x^2}$ ning qiymatini toping.