$3x^2 - 5x + 1 = 0$ tenglamani normal ko'rinishga keltiring.
- A. $x^2 - \frac{5}{3}x + 1 = 0$
- B. $x^2 - \frac{5}{3}x + \frac{1}{3} = 0$
- C. $x^2 - 5x + \frac{1}{3} = 0$
- D. $\frac{1}{3}x^2 - \frac{5}{3}x + \frac{1}{3} = 0$
Javob: $x^2 - \frac{5}{3}x + \frac{1}{3} = 0$
Bu savol Viyet teoremasi mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganish