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Algebra · oson

Viyet teoremasi bo‘yicha savol

$-2x^2 - 10x + 8 = 0$ tenglamani normal ko'rinishga keltiring.
  1. A. $x^2 + 5x + 4 = 0$
  2. B. $x^2 - 5x - 4 = 0$
  3. C. $-x^2 -5x +4 = 0$
  4. D. $x^2 + 5x - 4 = 0$
Javob va yechimni ko‘rish

Javob: $x^2 + 5x - 4 = 0$

Mavzuni mustahkamlang

Bu savol Viyet teoremasi mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

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