$-2x^2 - 10x + 8 = 0$ tenglamani normal ko'rinishga keltiring.
- A. $x^2 + 5x + 4 = 0$
- B. $x^2 - 5x - 4 = 0$
- C. $-x^2 -5x +4 = 0$
- D. $x^2 + 5x - 4 = 0$
Javob: $x^2 + 5x - 4 = 0$
Bu savol Viyet teoremasi mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganish