100 sonining barcha natural bo'luvchilarini yozing.
- A. 1, 2, 4, 5, 10, 20, 25, 50, 100, 0
- B. 1, 2, 4, 5, 20, 25, 50, 100
- C. 1, 2, 4, 5, 11, 20, 25, 50, 100
- D. 1, 2, 4, 5, 10, 20, 25, 50, 100
Bo'linish belgilari, tub va murakkab sonlar bo‘yicha savol
Javob va yechimni ko‘rish
Javob: 1, 2, 4, 5, 10, 20, 25, 50, 100
100 sonining bo‘luvchilarini topish uchun avvalo 100 ni tub ko‘paytuvchilari shaklida yozamiz: $100 = 2^{2}\cdot 5^{2}$. Har bir tub ko‘paytuvchidan $0,1,2$ darajalarini tanlab, ularning barcha kombinatsiyalarini olish orqali bo‘luvchilar hosil bo‘ladi: $2^{a}\cdot5^{b}$, bu yerda $a,b\in\{0,1,2\}$. $a$ va $b$ ning barcha juftliklari $ (0,0),(1,0),(2,0),(0,1),(1,1),(2,1),(0,2),(1,2),(2,2)$ beradi va ularning mahsulotlari $1,2,4,5,10,20,25,50,100$ ga teng. Shunday qilib, 100 ning barcha natural bo‘luvchilari $1, 2, 4, 5, 10, 20, 25, 50, 100$ dir, ya’ni variant **D** to‘g‘ri.
Mavzuni mustahkamlang
Bu savol Bo'linish belgilari, tub va murakkab sonlar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganish