Algebra · orta

Ratsional tenglamalar bo‘yicha savol

$ (2x + 3)^2 + 12(2x + 3) + 35 = 0 $

A. $-5;-\frac{3}{4}$
B. $-4;-\frac{1}{2}$
C. $-3;-\frac{1}{4}$
D. $-6;-\frac{5}{4}$

Javob va yechimni ko‘rish

Javob: $-5;-\frac{3}{4}$

Mavzuni mustahkamlang

Bu savol Ratsional tenglamalar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

Mavzuni o‘rganish

Shu mavzudagi boshqa savollar

$ (2x - 1)^2 + 8(2x - 1) + 15 = 0 $$ (3x - 2)^2 - 9(3x - 2) + 8 = 0 $$ 3(x + 2)^2 + 10(x + 2) + 3 = 0 $$ (x^2 + 2x)^2 - 2(x^2 + 2x) - 3 = 0 $$ (x^2 + 1)^2 - 6(x^2 + 1) + 5 = 0 $