Algebra · orta

Ratsional tenglamalar bo‘yicha savol

$ (x^2 + 1)^2 - 6(x^2 + 1) + 5 = 0 $

A. $-2;0;2$
B. $-1;1;3$
C. $-3;-1;1$
D. $-4;0;4$

Javob va yechimni ko‘rish

Javob: $-2;0;2$

Mavzuni mustahkamlang

Bu savol Ratsional tenglamalar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

Mavzuni o‘rganish

Shu mavzudagi boshqa savollar

$ (2x - 1)^2 + 8(2x - 1) + 15 = 0 $$ (3x - 2)^2 - 9(3x - 2) + 8 = 0 $$ 3(x + 2)^2 + 10(x + 2) + 3 = 0 $$ (2x + 3)^2 + 12(2x + 3) + 35 = 0 $$ (x^2 + 2x)^2 - 2(x^2 + 2x) - 3 = 0 $