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Bo'linuvchanlik. Sonning natural bo'luvchilar soni va yig'indisi bo‘yicha savol

56 sonining natural bo'luvchilari yig'indisini toping.
  1. A. 120
  2. B. 110
  3. C. 116
  4. D. 117
Javob va yechimni ko‘rish

Javob: 120

56 sonining tub ko‘paytuvchilari $2^{3}\cdot7$ ga teng. Agar $n=p_{1}^{a_{1}}p_{2}^{a_{2}}\dots p_{k}^{a_{k}}$ bo‘lsa, uning barcha natural bo‘luvchilar yig‘indisi $\displaystyle \prod_{i=1}^{k}\frac{p_{i}^{\,a_{i}+1}-1}{p_{i}-1}$ formulasi bilan hisoblanadi. Demak, \[ \text{yig‘indi}= \frac{2^{3+1}-1}{2-1}\cdot\frac{7^{1+1}-1}{7-1} = \frac{2^{4}-1}{1}\cdot\frac{7^{2}-1}{6} = (16-1)\cdot\frac{49-1}{6} = 15\cdot 8 =120. \] Shu sababli 56 sonining natural bo‘luvchilar yig‘indisi **120** ga teng.

Mavzuni mustahkamlang

Bu savol Bo'linuvchanlik. Sonning natural bo'luvchilar soni va yig'indisi mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

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