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Bo'linuvchanlik. Sonning natural bo'luvchilar soni va yig'indisi bo‘yicha savol

240 sonining natural bo'luvchilari yig'indisini toping.
  1. A. 744
  2. B. 742
  3. C. 747
  4. D. 1488
Javob va yechimni ko‘rish

Javob: 744

$240$ sonini tub ko‘paytuvchilarga ajratamiz: $240 = 2^{4}\cdot 3^{1}\cdot 5^{1}$. Agar $n=p_{1}^{a_{1}}p_{2}^{a_{2}}\dots p_{k}^{a_{k}}$ bo‘lsa, $n$ ning barcha natural bo‘luvchilarining yig‘indisi quyidagi formulaga teng: \[ \sigma (n)=\prod_{i=1}^{k}\frac{p_{i}^{\,a_{i}+1}-1}{p_{i}-1}. \] Shu formulani $240$ ga qo‘llaymiz: \[ \sigma (240)=\frac{2^{4+1}-1}{2-1}\cdot\frac{3^{1+1}-1}{3-1}\cdot\frac{5^{1+1}-1}{5-1} =\frac{32-1}{1}\cdot\frac{9-1}{2}\cdot\frac{25-1}{4} =31\cdot4\cdot6=744. \] Demak, $240$ sonining barcha natural bo‘luvchilarining yig‘indisi $\boxed{744}$, ya’ni variant **A**.

Mavzuni mustahkamlang

Bu savol Bo'linuvchanlik. Sonning natural bo'luvchilar soni va yig'indisi mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

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