MathTest.uz
Algebra · oson

Bo'linuvchanlik. Sonning natural bo'luvchilar soni va yig'indisi bo‘yicha savol

Hisoblash natijasida hosil bo'lgan sonning natural bo'luvchilari sonini toping: $100\cdot 198\cdot 324$
  1. A. 242
  2. B. 255
  3. C. 252
  4. D. 257
Javob va yechimni ko‘rish

Javob: 252

Berilgan sonni tub ko‘paytuvchilarga ajrating: $100=2^{2}\cdot5^{2}$, $198=2\cdot3^{2}\cdot11$, $324=2^{2}\cdot3^{4}$. Shu bilan $100\cdot198\cdot324=2^{5}\cdot3^{6}\cdot5^{2}\cdot11$. Agar $n=p_{1}^{a_{1}}p_{2}^{a_{2}}\dots p_{k}^{a_{k}}$ bo‘lsa, $n$ ning natural bo‘luvchilari soni $\displaystyle (a_{1}+1)(a_{2}+1)\dots (a_{k}+1)$. Bu holda $(5+1)(6+1)(2+1)(1+1)=6\cdot7\cdot3\cdot2=252$. Demak, to‘g‘ri javob **C) 252**.

Mavzuni mustahkamlang

Bu savol Bo'linuvchanlik. Sonning natural bo'luvchilar soni va yig'indisi mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.

Mavzuni o‘rganish

Shu mavzudagi boshqa savollar