$a,b,c$ sonlarini o'sish tartibida joylashtiring: $a=\frac{6}{11}; b=\frac{9}{17}$ va $c=\frac{3}{5}$
- A. c<a<b
- B. b<a<c
- C. c<b<a
- D. b<c<a
Oddiy kasrlar va ular ustida amallar bo‘yicha savol
Javob va yechimni ko‘rish
Javob: b<a<c
Kasrlarni taqqoslashda har birini o’nli son shakliga o'tkazamiz.
$a=\frac{6}{11}=0.545\ldots$, $b=\frac{9}{17}=0.529\ldots$, $c=\frac{3}{5}=0.600$.
Endi sonlarni o’sish tartibida solishtiramiz: $b\;(0.529)<a\;(0.545)<c\;(0.600)$.
Shu sababli to‘g‘ri tartib **b < a < c**, ya’ni variant **B**.
Mavzuni mustahkamlang
Bu savol Oddiy kasrlar va ular ustida amallar mavzusiga tegishli. Ta’riflar, formulalar va misollarni mavzu sahifasida ko‘ring.
Mavzuni o‘rganishShu mavzudagi boshqa savollar
$\frac{3}{4}+\frac{5}{6}-\frac{2}{3}$ ifodasini soddalashtiring.$\frac{7}{9}\times\frac{3}{14}$ ni hisoblang va soddalashtiring.$\frac{x}{5}-\frac{2}{3}=\frac{1}{15}$ tenglamasida $x$ ni toping.$\frac{2}{5}\div\left(\frac{4}{15}\right)+\frac{1}{2}$ ifodasini hisoblang.Agar $\frac{3}{x}=\frac{9}{12}$ bo‘lsa, $x$ ni toping va $x-\frac{1}{4}$ ning qiymatini hisoblang.